379. Design Phone Directory
Design a Phone Directory which supports the following operations:
- get: Provide a number which is not assigned to anyone.
- check: Check if a number is available or not.
- release: Recycle or release a number.
Example:
// Init a phone directory containing a total of 3 numbers: 0, 1, and 2.
PhoneDirectory directory = new PhoneDirectory(3);
// It can return any available phone number. Here we assume it returns 0.
directory.get();
// Assume it returns 1.
directory.get();
// The number 2 is available, so return true.
directory.check(2);
// It returns 2, the only number that is left.
directory.get();
// The number 2 is no longer available, so return false.
directory.check(2);
// Release number 2 back to the pool.
directory.release(2);
// Number 2 is available again, return true.
directory.check(2);
S1: hashset & rand
存储已有的电话号码,每次随机生成,当使用过的号码很多时随机事件会很长
class PhoneDirectory {
public:
/** Initialize your data structure here
@param maxNumbers - The maximum numbers that can be stored in the phone directory. */
PhoneDirectory(int maxNumbers) {
n = maxNumbers;
}
/** Provide a number which is not assigned to anyone.
@return - Return an available number. Return -1 if none is available. */
int get() {
if (used.size() == n) return -1;
int num = rand() % n;
while (used.find(num) != used.end()) {
num = rand() % n;
}
used.insert(num);
return num;
}
/** Check if a number is available or not. */
bool check(int number) {
if (number < 0 || number >= n || used.find(number) != used.end()) return false;
return true;
}
/** Recycle or release a number. */
void release(int number) {
if (used.find(number) != used.end()) used.erase(number);
}
private:
int n;
unordered_set<int> used;
};
S2:两个数组,顺序取号码
两个数组,一个存储可用的电话号码,顺序取出。一个存储每个号码对应在第一个数组中的index,除了初始函数外都是O(1)的操作
class PhoneDirectory {
public:
/** Initialize your data structure here
@param maxNumbers - The maximum numbers that can be stored in the phone directory. */
PhoneDirectory(int maxNumbers) {
idx = 0;
nums.resize(maxNumbers);
numToIdx = vector<int>(maxNumbers, -1);
for (int i = 0; i < maxNumbers; ++i) nums[i] = i;
}
/** Provide a number which is not assigned to anyone.
@return - Return an available number. Return -1 if none is available. */
int get() {
if (idx == nums.size()) return -1;
numToIdx[nums[idx]] = idx;
return nums[idx++];
}
/** Check if a number is available or not. */
bool check(int number) {
if (number >= 0 && number < nums.size() && numToIdx[number] == -1) return true;
return false;
}
/** Recycle or release a number. */
void release(int number) {
if (number < 0 || number >= nums.size() || numToIdx[number] == -1) return;
int i = numToIdx[number];
idx--;
numToIdx[nums[idx]] = i;
numToIdx[number] = -1;
swap(nums[i], nums[idx]);
}
private:
int idx;
vector<int> nums;
vector<int> numToIdx;
};